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(T)=5T^2+2
We move all terms to the left:
(T)-(5T^2+2)=0
We get rid of parentheses
-5T^2+T-2=0
a = -5; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-5)·(-2)
Δ = -39
Delta is less than zero, so there is no solution for the equation
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